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A174198
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Floor of inverse of Minkowski's constant.
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1
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0, 1, 3, 8, 20, 50, 128, 326, 838, 2164, 5613, 14619, 38200, 100109, 263002, 692452, 1826640, 4826740, 12773610, 33850507, 89815472, 238573535, 634359840, 1688317073, 4497222961, 11988860360, 31983701435, 85383496739, 228083043888
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OFFSET
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1,3
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COMMENTS
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The subsequence of primes begins: 3, 100109. As a final application of Minkowski's theorem, Stevenhagen shows that the unit group of an order R in a number field with r real and 2s complex embeddings is finitely generated of free rank r + s - 1 (Dirichlet unit theorem).
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LINKS
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P. Stevenhagen, Number Rings, Chapter 5, Geometry of numbers.
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FORMULA
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EXAMPLE
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a(0) = floor((1^1)*Pi/(4*1!)) = floor(0.78539816339744830962) = 0.
a(10) = floor((10^10)*Pi/(4*10!)) = floor(2164.3467906675714) = 2164.
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MAPLE
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CROSSREFS
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KEYWORD
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easy,nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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