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A174006 An antidiagonal triangle based on: t(n,q) = q^(n - 1) + (q - 1)*cos(n*Pi/2). 0
1, 1, 1, 4, 1, 1, 9, 9, 1, 1, 16, 29, 16, 1, 1, 31, 81, 67, 25, 1, 1, 64, 241, 256, 129, 36, 1, 1, 129, 729, 1021, 625, 221, 49, 1, 1, 256, 2189, 4096, 3121, 1296, 349, 64, 1, 1, 511, 6561, 16387, 15625, 7771, 2401, 519, 81, 1, 1 (list; table; graph; refs; listen; history; text; internal format)
OFFSET

0,4

COMMENTS

Row sums are {1, 2, 6, 20, 63, 206, 728, 2776, 11373, 49858, ...}.

LINKS

Table of n, a(n) for n=0..54.

FORMULA

t(n,q) = q^(n - 1) + (q - 1)*cos(n*Pi/2).

EXAMPLE

{1},

{1, 1},

{4, 1, 1},

{9, 9, 1, 1},

{16, 29, 16, 1, 1},

{31, 81, 67, 25, 1, 1},

{64, 241, 256, 129, 36, 1, 1},

{129, 729, 1021, 625, 221, 49, 1, 1},

{256, 2189, 4096, 3121, 1296, 349, 64, 1, 1},

{511, 6561, 16387, 15625, 7771, 2401, 519, 81, 1, 1}

MATHEMATICA

g[n_, q_] = q^(n - 1) + (q - 1)*Cos[n*Pi/2];

a = Table[Table[g[n, q], {n, 1, 10}], {q, 2, 12}];

Table[Table[a[[m, n - m + 1]], {m, 1, n}], {n, 1, 10}];

Flatten[%]

CROSSREFS

Sequence in context: A176282 A082043 A177944 * A124216 A008459 A259333

Adjacent sequences:  A174003 A174004 A174005 * A174007 A174008 A174009

KEYWORD

nonn,tabl,uned

AUTHOR

Roger L. Bagula, Mar 05 2010

STATUS

approved

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Last modified October 15 04:33 EDT 2019. Contains 328026 sequences. (Running on oeis4.)