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Partial sums of A000133.
0

%I #2 Mar 30 2012 18:40:51

%S 2,7,37,2325,67174677,144115192370888981,

%T 1329227995784915891350551138284929301,

%U 226156424291633194186662080095093570366200305721017690121386945275228127509

%N Partial sums of A000133.

%C Partial sums of number of Boolean functions of n variables. The subsequence of primes in this partial sum begins: 2, 7, 37, 1329227995784915891350551138284929301. What is the next such prime?

%F a(n) = SUM[i=1..n] A000133(i) = SUM[i=1..n] (2^(2^i)+(2^i-1)*2^(2^(i-1)+1))/2^(i+1).

%e a(8) = 2 + 5 + 30 + 2288 + 67172352 + 144115192303714304 + 1329227995784915891206435945914040320 + 226156424291633194186662080095093570364871077725232774230036394136943198208.

%Y Cf. A000133.

%K easy,nonn

%O 1,1

%A _Jonathan Vos Post_, Feb 23 2010