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a(n) = floor(n/sqrt(6)).
1

%I #20 Sep 08 2022 08:45:50

%S 0,0,0,1,1,2,2,2,3,3,4,4,4,5,5,6,6,6,7,7,8,8,8,9,9,10,10,11,11,11,12,

%T 12,13,13,13,14,14,15,15,15,16,16,17,17,17,18,18,19,19,20,20,20,21,21,

%U 22,22,22,23,23,24,24,24,25,25,26,26,26,27,27,28,28,28,29,29,30,30

%N a(n) = floor(n/sqrt(6)).

%H Vincenzo Librandi, <a href="/A172476/b172476.txt">Table of n, a(n) for n = 0..1000</a>

%H <a href="/index/Be#Beatty">Index entries for sequences related to Beatty sequences</a>

%t Table[Floor[n Sqrt[6]/6], {n, 0, 80}] (* _Vincenzo Librandi_, Aug 01 2013 *)

%o (Magma) [Floor(n*Sqrt(6)/6): n in [0..80]]; // _Vincenzo Librandi_, Aug 01 2013

%Y Cf. A022840: floor(n/(sqrt(6)/6)), Beatty sequence of A020763.

%K nonn,easy

%O 0,6

%A _Vincenzo Librandi_, Feb 04 2010

%E Definition simplified by _N. J. A. Sloane_, Mar 11 2021