OFFSET
1,5
LINKS
G. C. Greubel, Table of n, a(n) for n = 1..4500
FORMULA
a(n) = floor((1/n)*(Fibonacci(n)*phi + Fibonacci(n-1)), where phi = (1+sqrt(5))/2.
MATHEMATICA
Table[Floor[((1 + Sqrt[5])/2)^n/n], {n, 1, 50}]
Table[Floor[GoldenRatio^n/n], {n, 50}] (* Harvey P. Dale, Dec 12 2018 *)
PROG
(Magma) [Floor((Lucas(n) + Sqrt(5)*Fibonacci(n))/(2*n)): n in [1..50]]; // G. C. Greubel, Apr 17 2022
(SageMath) [floor(golden_ratio^n/n) for n in (1..50)] # G. C. Greubel, Apr 17 2022
CROSSREFS
KEYWORD
nonn
AUTHOR
Clark Kimberling, Nov 20 2010
STATUS
approved