OFFSET
1,3
COMMENTS
Rows tend to the triangular series, A000217.
Let T(n) be the variants of the natural number decrescendo triangle, A004736; such that T(n) = A004736, prepending n ones to the leftmost column. Then take Lim_{k=1..inf} ((T(n))^k, left-shifted vectors considered as sequences = rows of the array, deleting the first 1. The rows of this triangle sequence are the truncated columns of the array with one "1" per row.
LINKS
Andrew Howroyd, Table of n, a(n) for n = 1..1275 (rows 1..50)
EXAMPLE
First few rows of the array are:
.
1, 3, 8, 21, 55, 144, 377, 987, ...
1, 1, 3, 6, 12, 24, 48, 96, ...
1, 1, 1, 3, 6, 10, 17, 30, ...
1, 1, 1, 1, 3, 6, 10, 15, ...
1, 1, 1, 1, 1, 3, 6, 10, ...
...
First few rows of the triangle =
1;
1, 3;
1, 3, 8;
1, 3, 6, 21;
1, 3, 6, 12, 55;
1, 3, 6, 10, 24, 144;
1, 3, 6, 10, 17, 48, 377;
1, 3, 6, 10, 15, 30, 96, 987;
1, 3, 6, 10, 15, 23, 53, 192, 2584;
1, 3, 6, 10, 15, 21, 37, 93, 384, 6765;
1, 3, 6, 10, 15, 21, 30, 61, 163, 768, 17711;
1, 3, 6, 10, 15, 21, 28, 45, 100, 286, 1536, 46368;
...
Example: Row 2 of the array is generated from a variant of A004736, the leftmost column with two prepended 1's, = T(2):
1;
1;
1;
2, 1;
3, 2, 1;
...
Take lim_{k->inf.} (P(2))^k, obtaining a left-shifted vector considered as a sequence; then delete the first 1, getting row 2 of the array.
PROG
(PARI)
T(n)={[Vec(p) | p<-Vec(sum(k=1, n, x^k*y^(k-1)*(1 - x^k)/((1 - x)*(1 - 2*x + x^2 - x^k)) + O(x*x^n)))]}
{ my(A=T(10)); for(n=1, #A, print(A[n])) } \\ Andrew Howroyd, Apr 13 2021
CROSSREFS
KEYWORD
nonn,tabl
AUTHOR
Gary W. Adamson, Dec 19 2009
EXTENSIONS
a(52) corrected and terms a(56) and beyond from Andrew Howroyd, Apr 13 2021
STATUS
approved