login
a(n) = 10^n*(2+3*10^n)+3.
1

%I #8 Sep 07 2022 22:13:58

%S 8,323,30203,3002003,300020003,30000200003,3000002000003,

%T 300000020000003,30000000200000003,3000000002000000003,

%U 300000000020000000003,30000000000200000000003,3000000000002000000000003,300000000000020000000000003,30000000000000200000000000003

%N a(n) = 10^n*(2+3*10^n)+3.

%H Colin Barker, <a href="/A171248/b171248.txt">Table of n, a(n) for n = 0..499</a>

%H <a href="/index/Rec#order_03">Index entries for linear recurrences with constant coefficients</a>, signature (111,-1110,1000).

%F a(n) = 111*a(n-1)-1110*a(n-2)+1000*a(n-3). - _Colin Barker_, May 31 2015

%F G.f.: -(3230*x^2-565*x+8) / ((x-1)*(10*x-1)*(100*x-1)). - _Colin Barker_, May 31 2015

%t CoefficientList[Series[(3230*x^2 - 565*x + 8)/((1 - x)*(10*x - 1)*(100*x - 1)), {x, 0, 20}], x] (* _Wesley Ivan Hurt_, Sep 07 2022 *)

%o (PARI) Vec(-(3230*x^2-565*x+8) / ((x-1)*(10*x-1)*(100*x-1)) + O(x^20)) \\ _Colin Barker_, May 31 2015

%K easy,nonn

%O 0,1

%A _Jason Earls_, Dec 06 2009