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a(n) = n^9*(n + 1)/2.
2

%I #11 Sep 08 2022 08:45:49

%S 0,1,768,39366,655360,5859375,35271936,161414428,603979776,1937102445,

%T 5500000000,14147686146,33538572288,74231495611,154957850880,

%U 307546875000,584115552256,1067290888473,1884413258496,3226876977790

%N a(n) = n^9*(n + 1)/2.

%H Vincenzo Librandi, <a href="/A170783/b170783.txt">Table of n, a(n) for n = 0..10000</a>

%H <a href="/index/Rec#order_11">Index entries for linear recurrences with constant coefficients</a>, signature (11,-55,165,-330,462,-462,330,-165, 55,-11,1).

%F G.f.: (x + 757*x^2 + 30973*x^3 + 264409*x^4 + 689155*x^5 + 621199*x^6 + 190783*x^7 + 16867*x^8 + 256*x^9)/(1-x)^11. - _G. C. Greubel_, Dec 05 2017

%F a(n) = 11*a(n-1)-55*a(n-2)+165*a(n-3)-330*a(n-4)+462*a(n-5)-462*a(n-6)+330*a(n-7)-165*a(n-8)+55*a(n-9)-11*a(n-10)+a(n-11). - _Wesley Ivan Hurt_, Apr 11 2022

%t Table[n^9*(n+1)/2, {n,0,30}] (* _G. C. Greubel_, Dec 05 2017 *)

%o (Magma) [n^9*(n+1)/2: n in [0..20]]; // _Vincenzo Librandi_, Aug 26 2011

%o (PARI) for(n=0, 30, print1(n^9*(n+1)/2, ", ")) \\ _G. C. Greubel_, Dec 05 2017

%K nonn,easy

%O 0,3

%A _N. J. A. Sloane_, Dec 11 2009