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A169660
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Triangle, read by rows, T(n, k) = binomial(n-1,k-1)*n!/k! + binomial(n-1, n-k)* n!/(n-k+1)! - n!.
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1
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1, 1, 1, 1, 6, 1, 1, 24, 24, 1, 1, 140, 120, 140, 1, 1, 1110, 780, 780, 1110, 1, 1, 10122, 8190, 3360, 8190, 10122, 1, 1, 100856, 101976, 30240, 30240, 101976, 100856, 1, 1, 1088712, 1332576, 512064, 60480, 512064, 1332576, 1088712, 1, 1, 12700890
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OFFSET
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1,5
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COMMENTS
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Row sums are: {1, 2, 8, 50, 402, 3782, 39986, 466146, 5927186, 81594182, ...}.
The first negative terms are T(11,6) = -11975040, T(12,6) = T(12,7) = -127733760, T(13,7) = -3943779840, T(14,7) = T(14,8) = -53785892160. - Hugo Pfoertner, Jul 16 2020
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LINKS
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FORMULA
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T(n, k) = binomial(n-1,k-1)*n!/k! + binomial(n-1, n-k)*n!/(n-k+1)! - n!.
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EXAMPLE
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Triangle begins as:
1;
1, 1;
1, 6, 1;
1, 24, 24, 1;
1, 140, 120, 140, 1;
1, 1110, 780, 780, 1110, 1;
1, 10122, 8190, 3360, 8190, 10122, 1;
1, 100856, 101976, 30240, 30240, 101976, 100856, 1;
1, 1088712, 1332576, 512064, 60480, 512064, 1332576, 1088712, 1;
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MAPLE
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b:=binomial; seq(seq( b(n-1, k-1)*n!/k! + b(n-1, n-k)*n!/(n-k+1)! -n!, k=1..n), n=1..10); # G. C. Greubel, Nov 28 2019
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MATHEMATICA
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T[n_, k_]:= Binomial[n-1, k-1]*n!/k! +Binomial[n-1, n-k]*n!/(n-k+1)! -n!; Table[T[n, m], {n, 10}, {k, n}]//Flatten (* modified by G. C. Greubel, Nov 28 2019 *)
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PROG
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(PARI) T(n, k) = binomial(n-1, k-1)*n!/k! + binomial(n-1, n-k)*n!/(n-k+1)! - n!; \\ G. C. Greubel, Nov 28 2019
(Magma) F:=Factorial; B:=Binomial; [B(n-1, k-1)*F(n)/F(k) + B(n-1, n-k)*F(n)/F(n - k+1) - F(n): k in [1..n], n in [1..10]]; // G. C. Greubel, Nov 28 2019
(Sage) f=factorial; b=binomial; [[b(n-1, k-1)*f(n)/f(k) + b(n-1, n-k)*f(n)/f(n - k+1) - f(n) for k in (1..n)] for n in (1..10)] # G. C. Greubel, Nov 28 2019
(GAP) F:=Factorial;; B:=Binomial;; Flat(List([1..10], n-> List([1..n], k->
B(n-1, k-1)*F(n)/F(k) + B(n-1, n-k)*F(n)/F(n - k+1) - F(n) ))); # G. C. Greubel, Nov 28 2019
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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