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A168661 a(n) = n^7*(n^4 + 1)/2. 1

%I #10 Sep 08 2022 08:45:49

%S 0,1,1088,89667,2105344,24453125,181538496,989075143,4296015872,

%T 15692921289,50005000000,142665578891,371522101248,896111571277,

%U 2024835291584,4324963359375,8796227239936,17136153323153

%N a(n) = n^7*(n^4 + 1)/2.

%H Vincenzo Librandi, <a href="/A168661/b168661.txt">Table of n, a(n) for n = 0..10000</a>

%H <a href="/index/Rec#order_12">Index entries for linear recurrences with constant coefficients</a>, signature (12,-66,220,-495,792,-924,792,-495,220,-66,12,-1).

%F From _G. C. Greubel_, Jul 28 2016: (Start)

%F G.f.: x*(1 + 1076*x + 76677*x^2 + 1100928*x^3 + 4868154*x^4 + 7864728*x^5 + 4868154*x^6 + 1100928*x^7 + 76677*x^8 + 1076*x^9 + x^10)/(1 - x)^12.

%F E.g.f.: (1/2)*x*(2 + 1086*x + 28802*x^2 + 146100*x^3 + 246870*x^4 + 179508*x^5 + 63988*x^6 + 11880*x^7 + 1155*x^8 + 55*x^9 + x^10)*exp(x). (End)

%t Table[n^7*(n^4 + 1)/2, {n,0,25}] (* _G. C. Greubel_, Jul 28 2016 *)

%o (Magma) [n^7*(n^4+1)/2: n in [0..20]]; // _Vincenzo Librandi_, Aug 28 2011

%o (PARI) a(n)=n^7*(n^4+1)/2 \\ _Charles R Greathouse IV_, Jul 29 2016

%K nonn,easy

%O 0,3

%A _N. J. A. Sloane_, Dec 11 2009

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Last modified April 24 17:29 EDT 2024. Contains 371962 sequences. (Running on oeis4.)