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A168378
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a(n) = 3 + 8*floor(n/2).
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2
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3, 11, 11, 19, 19, 27, 27, 35, 35, 43, 43, 51, 51, 59, 59, 67, 67, 75, 75, 83, 83, 91, 91, 99, 99, 107, 107, 115, 115, 123, 123, 131, 131, 139, 139, 147, 147, 155, 155, 163, 163, 171, 171, 179, 179, 187, 187, 195, 195, 203, 203, 211, 211, 219, 219, 227, 227, 235, 235
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OFFSET
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1,1
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COMMENTS
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More generally, the sequences generated by the recursive relation b(n) = h*n - b(n-1) + k, with b(1)=c and h, k, c, prefixed integers, have the closed form b(n) = (2*h*n + (3*h + 2*k - 4*c)*(-1)^n + h + 2*k)/4. Also, if 2*c = h+k, then b(n) = c + h*floor(n/2); if 2*c = 2*h+k, then b(n) = c + h*floor((n-1)/2); if 2*c = k, b(n) = c + h*floor((n+1)/2). - Bruno Berselli, Sep 18 2013
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LINKS
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FORMULA
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a(n) = 8*n - a(n-1) - 2, with n>1, a(1)=3.
E.g.f.: (4*x + 3)*cosh(x) + (4*x - 1)*sinh(x) - 3. - G. C. Greubel, Jul 19 2016
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MATHEMATICA
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CoefficientList[Series[(3 + 8 x - 3 x^2)/((1 + x) (x - 1)^2), {x, 0, 70}], x] (* Vincenzo Librandi, Sep 18 2013 *)
LinearRecurrence[{1, 1, -1}, {3, 11, 11}, 80] (* Harvey P. Dale, Oct 05 2022 *)
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PROG
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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