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A168179 a(n) = n^3*(n^4 + 1)/2. 1

%I #16 Sep 08 2022 08:45:48

%S 0,1,68,1107,8224,39125,140076,411943,1048832,2391849,5000500,9744251,

%T 17916768,31375357,52708124,85431375,134219776,205171793,306112932,

%U 446939299,640004000,900548901,1247184268,1702418807,2293242624

%N a(n) = n^3*(n^4 + 1)/2.

%H Vincenzo Librandi, <a href="/A168179/b168179.txt">Table of n, a(n) for n = 0..480</a>

%F G.f.: x*(1+60*x+591*x^2+1216*x^3+591*x^4+60*x^5+x^6)/(1-x)^8. - _Vincenzo Librandi_, Jul 15 2016

%t Table[n^3*(n^4 + 1)/2, {n,0,50}] (* _G. C. Greubel_, Jul 15 2016 *)

%t CoefficientList[Series[x (1 + 60 x + 591 x^2 + 1216 x^3 + 591 x^4 + 60 x^5 + x^6) /(1-x)^8, {x, 0, 33}], x] (* _Vincenzo Librandi_, Jul 15 2016 *)

%o (Magma) [n^3*(n^4+1)/2: n in [0..50]]; // _Vincenzo Librandi_, Apr 25 2011

%K nonn

%O 0,3

%A _N. J. A. Sloane_, Dec 11 2009

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Last modified April 23 19:56 EDT 2024. Contains 371916 sequences. (Running on oeis4.)