%I #5 Mar 31 2012 21:08:40
%S 1,2,6,3,10,12,4,13,20,14,5,18,25,22,24,7,21,36,29,40,26,8,27,41,38,
%T 49,42,28,9,34,51,45,72,53,44,30,11,37,68,59,81,74,57,46,48,15,43,73,
%U 70,99,85,76,61,80,50,16,55,83,77,136,107,89,78,97,82,52
%N Linearize the arrays A099627 A124922 ... defined in A167204 and based on A161924 then concatenate to form a new table.
%C Contribution from _Alford Arnold_, Nov 29 2009: (Start)
%C Note that the values within A167977 identify the number partitioned described in A125106 and A161924.
%C (End)
%e The resulting table begins:
%e ..1..2..3..4..5..7..8
%e ..6.10.13.18.21.27
%e .12.20.25.36.41
%e .14.22.29.38
%e etc.
%e Contribution from _Alford Arnold_, Nov 29 2009: 4 equals 2+2 which maps to the natural number 6 (binary 110) and 6 appears in the second array (A124922).
%Y Cf. A099627 A124922 A167204 A161924
%Y Contribution from _Alford Arnold_, Nov 29 2009: (Start)
%Y A125106(Describes the mapping to partitions). A167977 is A161511(A167979).
%Y (End)
%K nonn,tabl,uned
%O 1,2
%A _Alford Arnold_, Nov 15 2009
%E Corrected By _Alford Arnold_, Nov 29 2009