OFFSET
1,1
COMMENTS
A167859(n) = 4^n*Sum_{ k=0..n } ((binomial(2*k,k))^2)/4^k.
PROG
(PARI) is(p) = if(isprime(p)&&p%2, my(m=Mod(1, p), s=m); for(k=1, p\2, s+=(m*=(2*k-1)/k)^2); !s, 0); \\ Jinyuan Wang, Jul 24 2022
CROSSREFS
KEYWORD
nonn
AUTHOR
Alexander Adamchuk, Nov 13 2009
EXTENSIONS
More terms from Jinyuan Wang, Jul 24 2022
STATUS
approved