OFFSET
1,1
COMMENTS
Sequence A167153 consists of runs of numbers of the same parity. It is conjectured that each time the parity changes, there is a gap of 3 numbers, and the sequence goes on with the successor a(n)+1 (of opposite parity) of the first "missing" term a(n) in the run of terms of given parity (a(n-1)+1, a(n-1)+3, ..., a(n)-2).
LINKS
E. Angelini, a(n) is the digitsum of a(a(n)), November 2009.
E. Angelini, a(n) is the digitsum of a(a(n)) [Cached copy, with permission]
EXAMPLE
Sequence A167153 starts 10,12,14,... so a(1)=9 is the predecessor of the first even term 10 = a(1)+1 in the sequence.
Then the sequence changes parity at ...,26, 28, 31, 33,..., i.e. a(2)-2 = 28 is the last term in this run of even numbers, a(2) = 30 is missing, and the sequence goes on with odd numbers starting at a(2)+1 = 31.
That run of odd numbers ends with a(3)-2 = 47; a(3) = 49 is missing, and the sequence goes on with even numbers starting at a(3)+1 = 50.
CROSSREFS
KEYWORD
more,nonn,base
AUTHOR
Eric Angelini and M. F. Hasler, Nov 03 2009
STATUS
approved