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 A166407 a(n) = floor(3*(A166406(n)/A005408(n))). 3
 -3, 1, 0, 3, -9, 3, 0, 6, 0, 3, 0, 9, -30, 1, 0, 9, 0, 6, 0, 12, 0, 3, 0, 15, -63, 6, 0, 12, 0, 9, 0, 6, 0, 3, 0, 21, 0, 2, 0, 15, -81, 9, 0, 18, 0, 6, 0, 24, 0, 0, 0, 15, 0, 9, 0, 24, 0, 6, 0, 30, -165, 6, 0, 15, 0, 15, 0, 6, 0, 9, 0, 30, 0, 0, 0, 21, 0, 12, 0, 30, 0, 3, 0, 33, -234, 6, 0, 6 (list; graph; refs; listen; history; text; internal format)
 OFFSET 0,1 COMMENTS Conjecture: the quotient A166406(i)/A005408(i) has denominator 3 when i is one of the terms of A166101, and it is integral in other cases. If true, then floor in the formula is unnecessary. LINKS A. Karttunen, Table of n, a(n) for n = 0..65535 CROSSREFS Cf. A166408. Sequence in context: A215771 A110033 A213666 * A159059 A127569 A117372 Adjacent sequences:  A166404 A166405 A166406 * A166408 A166409 A166410 KEYWORD sign AUTHOR Antti Karttunen, Oct 21 2009 STATUS approved

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