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 A165988 First trisection of A022998. 6
 0, 3, 12, 9, 24, 15, 36, 21, 48, 27, 60, 33, 72, 39, 84, 45, 96, 51, 108, 57, 120, 63, 132, 69, 144, 75, 156, 81, 168, 87, 180, 93, 192, 99, 204, 105, 216, 111, 228, 117, 240, 123, 252, 129, 264, 135, 276, 141, 288, 147, 300, 153, 312, 159, 324, 165, 336, 171, 348, 177 (list; graph; refs; listen; history; text; internal format)
 OFFSET 0,2 COMMENTS Read modulo 10, this yields a sequence with a period of length 10 containing all 10 digits: 0, 3, 2, 9, 4, 5, 6, 1, 8, 7. The other two trisections start 1, 8, 7, 20, 13, 32, 19, 44.... and 4, 5, 16, 11, 28, 17, 40, 23.... The Pisano period lengths for reading the sequence modulo m>=1 are 1,  2,  1,  4, 10,  2, 14,  8,  6, 10, 22,  4, 26, 14, 10, 16, 34,  6, 38, 20, 14, 22, 46,  8, 50, 26, 18, 28, 58... - R. J. Mathar, Oct 08 2011 LINKS G. C. Greubel, Table of n, a(n) for n = 0..5000 Index entries for linear recurrences with constant coefficients, signature (0,2,0,-1). FORMULA a(n) = A022998(3n) = 3*A022998(n) = 3*n*(3 +(-1)^n)/2 . a(n) = 2*a(n-2) - a(n-4). G.f.: 3*x*(1+4*x+x^2)/((x-1)^2 *(1+x)^2). E.g.f.: 3*x*(-1 + 3*exp(2*x))*exp(-x)/2. - Ilya Gutkovskiy, Apr 21 2016 MATHEMATICA LinearRecurrence[{0, 2, 0, -1}, {0, 3, 12, 9}, 50] (* G. C. Greubel, Apr 20 2016 *) PROG (PARI) a(n) = my(n=3*n); if (n % 2, n, 2*n); \\ Michel Marcus, Apr 21 2016 CROSSREFS Cf. A165351, A165355, A165367. Sequence in context: A239932 A114237 A060035 * A298028 A215842 A018876 Adjacent sequences:  A165985 A165986 A165987 * A165989 A165990 A165991 KEYWORD nonn,easy AUTHOR Paul Curtz, Oct 03 2009 STATUS approved

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Last modified August 21 02:36 EDT 2018. Contains 313930 sequences. (Running on oeis4.)