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A165772
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Numbers d*p where d is a perfect number and p<d a prime not dividing d.
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3
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30, 84, 140, 308, 364, 476, 532, 644, 1488, 2480, 3472, 5456, 6448, 8432, 9424, 11408, 14384, 18352, 20336, 21328, 23312, 24384, 26288, 29264, 30256, 33232, 35216, 36208, 39184, 40640, 41168, 44144, 48112, 50096, 51088, 53072, 54064, 56048
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OFFSET
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1,1
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COMMENTS
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A subsequence of A109321, and thus admirable numbers (A111592, solutions to sigma(x)-2x = 2d with d being a proper divisor of x): If d is a perfect number (A000396), then for any prime p<d coprime to d, sigma(dp)-2dp = 2d (thus dp is in A111592) and d > sqrt(dp).
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LINKS
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EXAMPLE
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For d=6=2*3, we get a(1)=5d=30.
For d=28=4*7, we get a(2)=3d=84, a(3)=5d=140, omitting 7d, a(4)=11d=308, a(5)=13d=364, a(6)=17d=476, a(7)=19d=532, a(8)=23d=644.
For d=496=16*31, we get a(9)=3d=1488 through a(21)=47d=23312 (omitting 31d), a(23)=53d=26288 through a(29)=39184, a(31)=41168 through a(38)=56048 and a(40)=62992.
For d=8128=64*127, we get a(22)=3d=24384, a(30)=5d=40640, a(39)=56896, a(41)=89408, and all following terms up to 3*4096*8191.
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MATHEMATICA
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f[p_] := (2^p - 1)*2^(p - 1); evenPerf[n_] := f[MersennePrimeExponent[n]]; sp[p_, max_] := With[{pn = f[p]}, pn * Select[Complement[Range[3, Min[pn - 1, max/pn]], {2^p - 1}], PrimeQ]];
seq[max_] := Module[{s = {}, k = 1}, While[(pn = evenPerf[k]) < max/3, s = Join[s, sp[MersennePrimeExponent[k], max]]; k++]; Union[s]]; seq[60000] (* Amiram Eldar, Aug 05 2023, assuming that there are no odd perfect numbers below max *)
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PROG
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(PARI) forprime(q=1, 9, isprime(2^q-1)|next; print("\n/* q="q", d=", d=(2^q-1)<<(q-1), " */"); forprime(p=3, d-1, d%p | next; print1(d*p, ", ")))
is_A165772(n)={ my(q=valuation(n, 2)); q | return; n=divrem(n>>q, 2^q-1); n[2]==0 && n[1] < (2^q-1)<<q && isprime(n[1]) }
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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