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%I #6 Jun 02 2015 08:27:32
%S 1,2,5,6,2,150,19,16,12,1536160080,8,9918821194590,300,188,65,
%T 341976204789992332560,157,2166703103992332274919550,24,450,3072320160
%N Minimal common difference of maximal arithmetic progression starting at n such that each term k has tau(k)=tau(n)
%C a(1) is not well defined, since the maximal progression has only one term.
%e For n=6, A165500(n)=3, and the least difference d such that tau(6) = tau(6+d) = tau(6+2d) is d=2, so a(6)=2.
%Y Cf. A165499, A165500, A088430.
%K hard,nonn,more
%O 2,2
%A _Hugo van der Sanden_, Sep 21 2009, Oct 09 2009
%E Extended to n=22 taking advantage of A088430 for n=19, _Hugo van der Sanden_, Jun 02 2015
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