a(n) = 1 for all odd n.
9 <= a(6) <= 13; a(8) = 17; 7 <= a(10) <= 8; 10 <= a(12) <= 103. (Improved bounds.  Hugo van der Sanden, Nov 29 2016)
a(10) >= 5, as witnessed by 43920665884407841463671+10*j, for j=0..4.  Giovanni Resta, Jul 28 2013
From Vladimir Letsko, Nov 12 2017: (Start)
a(10) >= 7 since tau(n+10*j) = 10 for j = 0..6, where n = 14050704001368114927829875896053677879533000445528831984807324824611106055054250255923644575057624816866566109483087319903747624457245979936363.
Congruences x^6 == 14 mod 3^5 and x^6 == 14 mod 3^5 have not solutions. On other hand tau(n+14*j) = 14 for j = 0..5, where n = 1330022329820905436281789742546819. Therefore a(14) = 5.
Similarly congruences x^18 == 38 mod 3^17 and x^18 == 38 mod 3^17 have not solutions. On other hand tau(n+38*j) = 38 for j = 0..5, where n = 4362267871759873721878756446028394403250067166871580001529317952259003864288330077973. Therefore a(38) = 5.
5 <= a(22) <= 8 since tau(n+22*j) = 22 for j = 0..5, where n = 1779938154456103755564381033732365223441543154296787.
5 <= a(26) <= 8 since tau(n+26*j) = 26 for j = 0..5, where n = 1245939824866421006701844954340329129368712284774265869140521.
5 <= a(34) <= 8 since tau(n+34*j) = 34 for j = 0..5, where n = 6938810980364904492570379879375548344505899946381175576077064821014404296739.
5 <= a(46) <= 8 since tau(n+46*j) = 46 for j = 0..5, where n = 238126419116398949002327631305276551305298646600638655722184434490882642040819831057336330413818359191.
5 <= a(58) <= 8 since tau(n+58*j) = 58 for j = 0..5, where n = 7704824180751624694570876810656527362795506581322310649236093848083558127895667820824262841185358447776614390313625335693359143.
5 <= a(62) <= 8 since tau(n+62*j) = 62 for j = 0..5, where n = 1815849596256775454944849876198119384742848046265852804696322354947434625695582072075372178480692269137534575212736614048480987548827877.
(End)
