|
|
FORMULA
| a(1) = 1, a(2) = 9, a(n) = product_{i=1..n-1} a(i), n >= 3. a(1) = 1, a(2) = 9, a(n) = A001019(2^(n-3)) = 9^(2^(n-3)), n >= 3. a(1) = 1, a(2) = 9, a(3) = 9, a(n) = (a(n-1))^2, n >= 4.
a(n)=A011764(n-2), n>2. [From R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Sep 20 2009]
|
