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%I #7 Mar 18 2022 13:33:06
%S 34,99,325,1161,4369,16929,66625,264321,1052929,4203009,16794625,
%T 67143681,268505089,1073881089,4295245825,17180426241,68720590849,
%U 274880135169,1099516084225,4398055424001,17592203870209,70368779829249
%N a(n) = (2^(n+4)+1)*(2^n+1).
%F a(n) = 7*a(n-1) -14*a(n-2)+8*a(n-3). G.f.: (34-139*x+108*x^2)/((1-x)*(2*x-1)*(4*x-1)). - R. J. Mathar, Sep 20 2009
%F a(n) = A000051(n) * A000051(n+4). - _Michel Marcus_, Jul 17 2013
%t Table[(2^(n+4)+1)(2^n+1),{n,0,30}] (* _Harvey P. Dale_, Mar 18 2022 *)
%o (PARI) a(n) = (2^(n+4)+1)*(2^n+1) \\ _Michel Marcus_, Jul 17 2013
%K nonn,easy
%O 0,1
%A Boris Hostnik (megpplus(AT)siol.net), Sep 08 2009
%E Two initial fractional values removed by _R. J. Mathar_, Sep 20 2009
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