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Length of cycle corresponding to n-th term of A165068
14

%I #4 Mar 30 2012 17:28:43

%S 1,1,6,1,2,3,1,1,1,2,7,2,2,1,1,2,1,1,2,1,2,2,1,1,2,1,1,2,2,2,1,2,2,2,

%T 1,1,2,2,1,1,2,1,2,2,2,1,2,2,2,2,1,1,1,1,2,2,2,1,1,1,2,2,2,1,2,2,2,1,

%U 2,1,2,2,2,2,2,1,1,2,2,2,1,2,2,1,1,2,2,2,1,2,2,2,2,1,2,2,1,1,2,1,2,2,2,2,2

%N Length of cycle corresponding to n-th term of A165068

%H Joseph Myers, <a href="/A165070/b165070.txt">Table of n, a(n) for n=1..23045</a>

%H <a href="/index/K#Kaprekar_map">Index entries for the Kaprekar map</a>

%Y Cf. A165051, A165056, A165068, A165069.

%Y In other bases: A000012 (base 2), A165011 (base 3), A165031 (base 4), A165050 (base 5), A165089 (base 7), A165109 (base 8), A165129 (base 9), A151966 (base 10).

%K base,nonn

%O 1,3

%A _Joseph Myers_, Sep 04 2009