login
A164942
Triangle, read by rows, T(n,k) = (-1)^k*binomial(n, k)*3^(n-k).
4
1, 3, -1, 9, -6, 1, 27, -27, 9, -1, 81, -108, 54, -12, 1, 243, -405, 270, -90, 15, -1, 729, -1458, 1215, -540, 135, -18, 1, 2187, -5103, 5103, -2835, 945, -189, 21, -1, 6561, -17496, 20412, -13608, 5670, -1512, 252, -24, 1, 19683, -59049, 78732, -61236, 30618, -10206, 2268, -324, 27, -1
OFFSET
0,2
COMMENTS
Rows sum up to A000079, antidiagonals sum up to A001906.
Triangle, read by rows, given by [3,0,0,0,0,0,0,0,...] DELTA [ -1,0,0,0,0,0,0,0,...] where DELTA is the operator defined in A084938. - Philippe Deléham, Sep 02 2009
Row n: expansion of (3-x)^n. - Philippe Deléham, Oct 09 2011
Essentially the same as the inverse of A027465, but with opposite signs in every other row. - M. F. Hasler, Feb 17 2020
The inverse of A027465 is (-1)^(n-k)*binomial(n, k)*3^(n - k). - G. C. Greubel, Feb 17 2020
FORMULA
T(n,k) = (-1)^n*(Inverse of A027465).
T(n,k) = 3*T(n-1,k) - T(n-1,k-1). - Philippe Deléham, Oct 09 2011
G.f.: 1/(1-3*x+x*y). - R. J. Mathar, Aug 11 2015
EXAMPLE
Begins as triangle:
1;
3, -1;
9, -6, 1;
27, -27, 9, -1;
81, -108, 54, -12, 1;
243, -405, 270, -90, 15, -1;
MAPLE
seq(seq( (-1)^k*binomial(n, k)*3^(n-k), k=0..n), n=0..10); # G. C. Greubel, Feb 17 2020
MATHEMATICA
With[{m = 9}, CoefficientList[CoefficientList[Series[1/(1-3*x+x*y), {x, 0, m}, {y, 0, m}], x], y]] // Flatten (* Georg Fischer, Feb 17 2020 *)
PROG
(Magma) [(-1)^k*Binomial(n, k)*3^(n-k): k in [0..n], n in [0..10]]; // G. C. Greubel, Feb 17 2020
(Sage) [[(-1)^k*binomial(n, k)*3^(n-k) for k in (0..n)] for n in (0..10)] # G. C. Greubel, Feb 17 2020
CROSSREFS
KEYWORD
sign,tabl
AUTHOR
Mark Dols, Sep 01 2009
EXTENSIONS
More terms from Philippe Deléham, Oct 09 2011
a(46) corrected by Georg Fischer, Feb 17 2020
Title changed by G. C. Greubel, Feb 17 2020
STATUS
approved