%I #9 Nov 02 2016 15:59:54
%S 1,100,1,10000,101,1,1000000,10101,102,1,100000000,1010101,10203,103,
%T 1,10000000000,101010101,1020304,10306,104,1,1000000000000,
%U 10101010101,102030405,1030610,10410,105,1,100000000000000,1010101010101
%N (100^n,1) Pascal triangle
%C (For row n=0,1,2,3,4,5 : Sum of digits = Pascal triangle)
%F T(n,0)=100^n, T(n,n)=1, T(n,k)=T(n-1,k-1)+T(n-1,k) for 0<k<n. - _Philippe Deléham_, Dec 27 2013
%F T(n,k)=101*T(n-1,k)+T(n-1,k-1)-100*T(n-2,k)-100*T(n-2,k-1), T(0,0)=1, T(1,0)=100, T(1,1)=1, T(n,k)=0 if k<0 or if k>n. - _Philippe Deléham_, Dec 27 2013
%e Triangle begins:
%e 1
%e 100,1
%e 10000,101,1
%e 1000000,10101,102,1
%e 100000000,1010101,10203,103,1
%e 10000000000,101010101,1020304,10306,104,1
%e 1000000000000,10101010101,102030405,1030610,10410,105,1
%e 100000000000000,1010101010101,10203040506,103061015,1041020,10515,106,1
%e 10000000000000000,101010101010101,1020304050607,10306101521,104102035,1051535,10621,107,1,
%Y Cf. A228196
%K nonn,tabl,easy
%O 0,2
%A _Mark Dols_, Aug 28 2009