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%I #4 Mar 31 2012 19:54:08
%S 1,4,9,16,49,169
%N Right-truncatable squares: every prefix is square.
%C This sequence is finite and 169 is the last term. If there were to be another term, it must have three digits and contract to either 16 or 49; or have four digits and contract to 169. No such square exists. [From _Sean A. Irvine_, Sep 08 2009]
%e a(6) = 169 since 169 is a perfect square and also 1 and 16 are perfect squares.
%K nonn,base,full,fini
%O 1,2
%A _Gaurav Kumar_, Aug 28 2009
%E Keywords full, fini from _Max Alekseyev_, Sep 11 2009
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