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A163491
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A fractal sequence (if we delete the first occurrence of n we get the sequence itself).
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5
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1, 1, 1, 2, 1, 2, 3, 1, 2, 4, 3, 1, 5, 2, 4, 6, 3, 1, 7, 5, 2, 8, 4, 6, 9, 3, 1, 10, 7, 5, 11, 2, 8, 12, 4, 6, 13, 9, 3, 14, 1, 10, 15, 7, 5, 16, 11, 2, 17, 8, 12, 18, 4, 6, 19, 13, 9, 20, 3, 14, 21, 1, 10, 22, 15, 7, 23, 5, 16, 24, 11, 2, 25, 17, 8, 26, 12
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OFFSET
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1,4
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COMMENTS
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Write the positive integers with two spaces between each integer: 1,_,_,2,_,_,3,_,_,4,_,_,5,_,_,6,..., and fill undefined places with the sequence itself. A003602 is obtained by starting from 1,_,2,_,3,_,4,_,5,_,6,....
a(n) - 1 is the row of A083044 in which n occurs.
The m-th occurrence of m is at position A083045(m-1).
(End)
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LINKS
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FORMULA
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a(3n-2) = n.
a(n+ceiling(n/2)) = a(n).
(End)
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EXAMPLE
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1,_,_,2,_,_,3,_,_,4,... -->
1,1,_,2,_,_,3,_,_,4,... -->
1,1,1,2,_,_,3,_,_,4,... -->
1,1,1,2,1,_,3,_,_,4,... -->
1,1,1,2,1,2,3,_,_,4,... -->
1,1,1,2,1,2,3,_,_,4,... -->
1,1,1,2,1,2,3,1,_,4,... -->
1,1,1,2,1,2,3,1,2,4,... -->
...
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MATHEMATICA
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a[n_] := a[n] = If[Mod[n, 3] == 1, (n+2)/3, a[Floor[2n/3]]];
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PROG
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(Python)
def a(n): return (n+2)//3 if n%3==1 else a(n*2//3)
(PARI) a(n) = n+=2; my(q, r); while([q, r]=divrem(n, 3); r, n-=q); q; \\ Kevin Ryde, Jan 16 2021
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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