OFFSET
0,1
COMMENTS
LINKS
G. C. Greubel, Table of n, a(n) for n = 0..500
Stuart Clary and Paul D. Hemenway, On sums of cubes of Fibonacci numbers, Applications of Fibonacci Numbers, Vol. 5 (St. Andrews, 1992), 123-136, Kluwer Acad. Publ., 1993. See equation (3).
Index entries for linear recurrences with constant coefficients, signature (20,-35,-35,20,-1).
FORMULA
a(n) = L(n)^2 * F(n+1)^2 * L(n-1) * F(n+2).
a(n) = (1/5)*(F(6n+3) - 12*F(2n+1) - 10*(-1)^n).
a(n) = F(2n+1)^3 - 3*F(2n+1) - 2*(-1)^n.
a(n) = 4*Sum_{k=2..n} F(2k)^3 = 4*A163199(n) if n is even.
a(n) = 4*Sum_{k=1..n} F(2k)^3 = 4*A163198(n) if n is odd.
a(n) - 21 a(n-1) + 56 a(n-2) - 21 a(n-3) + a(n-4) = - 200*(-1)^n.
a(n) - 20 a(n-1) + 35 a(n-2) + 35 a(n-3) - 20 a(n-4) + a(n-5) = 0.
G.f.: (-4 + 84*x - 112*x^2)/(1 - 20*x + 35*x^2 + 35*x^3 - 20*x^4 + x^5) = -4*(1 - 21*x + 28*x^2)/((1 + x)*(1 - 3*x + x^2)*(1 - 18*x + x^2)).
A163194(n) - a(n) = 4*(-1)^n.
MATHEMATICA
a[n_Integer] := LucasL[n]^2*Fibonacci[n+1]^2*LucasL[n-1] *Fibonacci[n+2]
LinearRecurrence[{20, -35, -35, 20, -1}, {-4, 4, 108, 2160, 39200}, 50] (* or *) Table[(1/5)*(Fibonacci[6*n+3] - 12*Fibonacci[2*n+1] - 10*(-1)^n), {n, 0, 25}] (* G. C. Greubel, Dec 09 2016 *)
PROG
(PARI) Vec( -4*(1 - 21*x + 28*x^2)/((1 + x)*(1 - 3*x + x^2)*(1 - 18*x + x^2)) + O(x^50)) \\ G. C. Greubel, Dec 09 2016
(PARI) for(n=0, 30, print1((1/5)*(fibonacci(6*n+3) - 12*fibonacci(2*n+1) - 10*(-1)^n), ", ")) \\ G. C. Greubel, Dec 21 2017
(Magma) [(Lucas(n)*Fibonacci(n+1))^2*(Lucas(n-1)*Fibonacci(n+2)): n in [0..30]]; // G. C. Greubel, Dec 21 2017
CROSSREFS
KEYWORD
sign,easy
AUTHOR
Stuart Clary, Jul 24 2009
STATUS
approved