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A162897
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a(1)=a(2)=2. a(n) = the smallest integer >= 2 such that a(n-1)^a(n) > a(n-2)^a(n-1).
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1
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2, 2, 3, 2, 4, 3, 4, 4, 5, 5, 6, 6, 7, 7, 8, 8, 9, 9, 10, 10, 11, 11, 12, 12, 13, 13, 14, 14, 15, 15, 16, 16, 17, 17, 18, 18, 19, 19, 20, 20, 21, 21, 22, 22, 23, 23, 24, 24, 25, 25, 26, 26, 27, 27, 28, 28, 29, 29, 30, 30, 31, 31, 32, 32, 33, 33, 34, 34, 35, 35, 36, 36, 37, 37, 38
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OFFSET
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1,1
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COMMENTS
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a(2n-1) = a(2n) = n, for all n >= 4.
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LINKS
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PROG
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(PARI) getnew(va, n) = {my(x = 2, y = va[n-2]^va[n-1]); while (va[n-1]^x <= y, x++); x; }
lista(nn) = {my(va = vector(nn)); va[1] = 2; va[2] = 2; for (n=3, nn, va[n] = getnew(va, n); ); va; } \\ Michel Marcus, Sep 05 2019
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CROSSREFS
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KEYWORD
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easy,nonn
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AUTHOR
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STATUS
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approved
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