|
|
A162892
|
|
Integers n such that the century defined by the interval [100n+1,100n+100] (i.e., the (n+1)-st century) contains exactly three Ormiston prime pairs.
|
|
1
|
|
|
651507, 1057749, 1263729, 1666162, 2527374, 3620083, 3850824, 4925140, 5418973, 8255451, 8300166, 8318772, 8389776, 9829099, 10876176, 11419227, 12195316, 14241925, 15170550, 15864637, 15876420, 16868593, 16892233, 17123505, 18032409
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,1
|
|
COMMENTS
|
Ormiston pairs must be of form (100n+13,100n+31), (100n+37,100n+73), (100n+79,100n+97).
There cannot be more than three Ormiston prime pairs in a century.
|
|
LINKS
|
|
|
PROG
|
(PARI) is(n)=isprime(100*n+13) && nextprime(100*n+17)==100*n+31 && isprime(100*n+37) && nextprime(100*n+39)==100*n+73 && isprime(100*n+79) && nextprime(100*n+81)==100*n+97 \\ Charles R Greathouse IV, Mar 07 2016
|
|
CROSSREFS
|
|
|
KEYWORD
|
base,nonn
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|