|
| |
|
|
A162692
|
|
Strictly positive numbers n such that 28*n/(28+n) are integers.
|
|
14
| | |
|
|
|
OFFSET
| 1,1
|
|
|
COMMENTS
| The 28th row of A127730.
The ansatz 28*n/(28+n)=j (any integer j) yields n=28*j/(28-j) which demonstrates that the sequence is finite if n>=0. [R. J. Mathar, Jul 13 2009]
|
|
|
MATHEMATICA
| f[a_, b_]:=(a*b)/(a+b); a=28; lst={}; Do[If[f[a, n]==IntegerPart[f[a, n]], AppendTo[lst, n]], {n, 9!}]; lst
|
|
|
CROSSREFS
| Cf. A162688, A162689, A162690, A162691
Cf. A127730. [From Franklin T. Adams-Watters (FrankTAW(AT)Netscape.net), Aug 07 2009]
Sequence in context: A168105 A048012 A130202 * A048067 A166647 A119107
Adjacent sequences: A162689 A162690 A162691 * A162693 A162694 A162695
|
|
|
KEYWORD
| nonn,fini,full
|
|
|
AUTHOR
| Vladimir Orlovsky (4vladimir(AT)gmail.com), Jul 10 2009
|
|
|
EXTENSIONS
| Edited by R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Jul 13 2009
|
| |
|
|
