|
| |
|
|
A162536
|
|
a(n) = the smallest positive multiple of n where every length of the runs of 0's and 1's in the binary representation of a(n) divides n.
|
|
2
| |
|
|
1, 2, 21, 4, 5, 6, 21, 16, 81, 10, 341, 12, 1365, 42, 285, 16, 85, 18, 87381, 20, 21, 22, 1398101, 24, 125, 26, 81, 84, 89478485, 90, 341, 256, 1815, 102, 1365, 36, 22906492245, 38, 117, 80, 349525, 42, 5461, 44, 4545, 598
(list; graph; refs; listen; history; internal format)
|
|
|
|
OFFSET
| 1,2
|
|
|
COMMENTS
| By "run" of 0's or 1's, it is meant: Think of binary n as a string of 0's and 1's. A single run of the digit b (0 or 1) is made up completely of consecutive digits all equal to b, and is bounded on its ends by either the digit 1-b or by the edge of the string.
|
|
|
EXAMPLE
| For n = 9, we check: 9 in binary is 1001, which has a run of two 0's, and 2 does not divide 9. Checking further: 2*9 = 18 = 10010, which still doesn't work. 3*9 = 27 = 11011 in binary, which has two runs of two 1's. 4*9 = 36 = 100100 in binary; 5*9 = 45 = 101101 in binary; 6*9 = 54 = 110110 in binary; 7*9 = 63 = 111111 in binary; 8*9 = 72 = 1001000 in binary; none of which work. But 9*9 = 81 = 1010001 in binary, which has three runs of one 1 each, a run of one 0, and a run of three 0's. Since 9 is divisible by both of these lengths (1 and 3), then a(9) = 81.
|
|
|
CROSSREFS
| Cf. A162534, A162537
Sequence in context: A055746 A060600 A143247 * A100980 A122509 A024230
Adjacent sequences: A162533 A162534 A162535 * A162537 A162538 A162539
|
|
|
KEYWORD
| base,more,nonn
|
|
|
AUTHOR
| Leroy Quet, Jul 05 2009
|
|
|
EXTENSIONS
| More terms from Sean A. Irvine (sairvin(AT)xtra.co.nz), Jan 26 2011
|
| |
|
|
