%I #4 Jun 02 2012 06:37:08
%S 7,9,11,13,19,21,22,23,25,27,29,31,33,35,37,38,39,41,45,47,49,50,53,
%T 54,55,57,59,61,62,63,65,66,67,69,71,73,74,75,77,79,81,82,83,86,87,89,
%U 91,92,93,94,95,97,98,99,101,103,105,106,107,108,109,110,111,113,114,115
%N Numbers n for which 2^^n != 2^2^n (mod n); for the "^^" notation see A092188.
%H Robert Munafo, <a href="http://www.mrob.com/pub/math/seq-a162002.html">2^^N == 2^(2^N) mod N</a>
%e 7 is in the sequence because 2^2^7 = 2^128 == 4 mod 7, but 2^^7 = 2^2^2^2^2^2^2 == 2 mod 7.
%Y Cf. A092188, A162002, A014221
%K easy,nonn
%O 1,1
%A _Robert Munafo_, Jun 24 2009