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A161905 a(n) = 13*a(n-1) - 65*a(n-2) + 156*a(n-3) - 182*a(n-4) + 91*a(n-5) - 13*a(n-6). 27
2, 4, 13, 52, 221, 949, 4056, 17186, 72163, 300482, 1241981, 5100758, 20833813, 84695026, 342920942, 1383646433, 5566235714, 22334785486, 89420529809, 357319721889, 1425447435997, 5678246483273, 22590565547134, 89775857333032, 356428030609222, 1413891596961194, 5604509198580578 (list; graph; refs; listen; history; text; internal format)
OFFSET

1,1

COMMENTS

a(n) is equal to the rational part (with respect of the field Q(sqrt(13))) of the product sqrt(2*(13-3*sqrt(13))/13)*X(2*n-1), where X(n) = sqrt((13 + 3*sqrt(13))/2)*X(n-1) - sqrt(13)*X(n-2) + sqrt((13 - 3*sqrt(13))/2)*X(n-3), with X(0)=3, X(1)=sqrt((13 + 3*sqrt(13))/2), and X(2)=(13 - sqrt(13))/2.

The Berndt-type sequence number 6 for the argument 2Pi/13 defined by the relation a(n) + A216540(n)*sqrt(13) = sqrt(2*(13-3*sqrt(13))/13)*X(2*n-1), where X(n) := s(2)^n + s(5)^n + s(6)^n, and s(j) := 2*sin(2*Pi*j/13), j=1,2,...,6.

We note that all numbers a(n+1)-4*a(n) for n=3,4,..., are divisible by 13. For example we have a(4)=4*a(3), a(5)-4*a(4)=13, a(6)-4*a(5)=5*13, a(7)-4*a(6)=20*13, and a(10)-4*a(9)=70*13^2.

a(n) is also equal to the rational part (with respect of the field Q(sqrt(13))) of the product sqrt(2*(13+3*sqrt(13))/13)*Y(2*n-1), where Y(n) = sqrt((13 - 3*sqrt(13))/2)*Y(n-1) + sqrt(13)*Y(n-2) - sqrt((13 + 3*sqrt(13))/2)*Y(n-3), with Y(0)=3, Y(1)=sqrt((13 - 3*sqrt(13))/2), and Y(2)=(13 + sqrt(13))/2. Let us observe that a(n) - A216540(n)*sqrt(13) = sqrt(2*(13+3*sqrt(13))/13)*Y(2*n-1) and Y(n) = s(1)^n + s(3)^n + s(9)^n (we have s(9) = -s(4)) - Roman Witula, Sep 22 2012

REFERENCES

R. Witula and D. Slota, Quasi-Fibonacci numbers of order 13 on the occasion of the Thirteenth International Conference on Fibonacci Numbers and their Applications, Congressus Numerantium, 201 (2010), 89-107.

R. Witula, On some applications of formulae for sums of the unimodular complex numbers, Wyd. Pracowni Komputerowej Jacka Skalmierskiego, Gliwice 2011 (in Polish).

LINKS

Table of n, a(n) for n=1..27.

Index to sequences with linear recurrences with constant coefficients, signature (13,-65,156,-182,91,-13).

FORMULA

G.f. -x*(-2+22*x-91*x^2+169*x^3-130*x^4+26*x^5) / ( 1-13*x+65*x^2-156*x^3+182*x^4-91*x^5+13*x^6 ). - R. J. Mathar, Sep 18 2012

EXAMPLE

It can be shown that 4*X(5) - X(7) = sqrt(26*(13+3*sqrt(13))), 4*X(7) - X(9) = 13*(sqrt(13) - 1)*sqrt(2*(13 + 3*sqrt(13)))/4, and  4*X(11) - X(13) = 130*(sqrt(13) - 2)*sqrt(2*(13 + 3*sqrt(13)))/4, which implies

(4*X(7) - X(9))/(4*X(5) - X(7)) = 13*(sqrt(13) - 1) and

(4*X(11) - X(13))/(4*X(7) - X(9)) = 10*(sqrt(13) - 2)/(sqrt(13) - 1) = 5*(11 - sqrt(13))/6.

We have also a(6)-a(3)-a(1)=4000, a(9)-2*a(4)-a(3)+3*a(1)=300000, and a(11)-a(5)+a(4)-2*a(2)-a(1)=5100000.

MATHEMATICA

LinearRecurrence[{13, -65, 156, -182, 91, -13}, {2, 4, 13, 52, 221, 949}, 30]

CROSSREFS

Cf. A216605, A216486, A216597, A216508, A216540.

Sequence in context: A058134 A069730 A072605 * A030953 A030811 A030917

Adjacent sequences:  A161902 A161903 A161904 * A161906 A161907 A161908

KEYWORD

sign,easy

AUTHOR

Roman Witula, Sep 12 2012

EXTENSIONS

Better name from Joerg Arndt, Sep 17 2012

STATUS

approved

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Last modified June 19 02:31 EDT 2013. Contains 226386 sequences.