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%I #10 Mar 11 2014 01:32:32
%S 2,3,5,7,11,13,17,19,23,25,29,31,37,38,39,41,43,44,47,49,51,53,59,61,
%T 67,69,71,73,79,81,83,85,86,87,89,91,97,101,103,104,107,109,113,115,
%U 116,118,127,128,131,133,134,137,139,141,142,143,145
%N a(1)=2. a(n) = the smallest integer > a(n-1) such that d(a(n)) <= d(n), where d(n) = the number of divisors of n.
%C Starting the sequence with a(1)=1 instead would have lead to a(n) = n for all n, obviously.
%Y Cf. A137518, A161576, A161577.
%K nonn
%O 1,1
%A _Leroy Quet_, Jun 14 2009
%E More terms from _Sean A. Irvine_, Feb 23 2011
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