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%I #2 Mar 30 2012 18:51:04
%S 0,1,0,2,2,0,0,3,3,3,0,0,0,0,0,4,4,4,4,0,0,0,0,0,0,0,0,0,0,0,0,5,5,5,
%T 5,5,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,6,6,6,6,6,
%U 6,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
%N Iteration of (k terms=k, followed by 2^k-k terms=0), beginning with k=0.
%C For n with 2^k - 1 <= n < 2^k + k-1: a(n) = k;
%C for n with 2^k + k-1 <= n < 2^(k+1) - 1: a(n) = 0.
%F a(n) = f(n,0) with f(n,k) = if n<2^k then (if n<k then k else 0) else f(n-2^k,k+1).
%Y A000225, A083706, A052944, A000918.
%K nonn,tabf
%O 0,4
%A _Reinhard Zumkeller_, May 24 2009
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