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A160371 The minimum size of a poset having n linear extensions. 2
0, 2, 3, 4, 4, 3, 5, 4, 5, 5, 5, 4, 6, 5, 5, 5, 7, 5, 6, 5, 6, 6, 6, 4, 5, 6, 6, 6, 7, 5, 7, 6, 6, 7, 6, 6, 6, 6, 7, 5, 7, 6, 7, 6, 6, 7, 7, 6, 7, 7, 7, 6, 7, 6, 7, 7, 6, 7, 8, 5, 6, 7, 7, 6, 7, 6, 7, 7, 7, 6, 7, 6, 7, 7, 6, 6, 7, 7, 7, 6, 7, 7, 8, 6, 8, 7, 7, 7, 8, 6, 7, 7, 7, 7, 7, 6, 8, 7, 7, 7, 7, 7 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,2
LINKS
Swee Hong Chan and Igor Pak, Computational complexity of counting coincidences, arXiv:2308.10214 [math.CO], 2023. See p. 12.
Swee Hong Chan and Igor Pak, Linear extensions and continued fractions, arXiv:2401.09723 [math.CO], 2024.
Bridget E. Tenner, Optimizing linear extensions, arXiv:0905.1688 [math.CO], 2009; SIAM J. Discr. Math. 23 (2009) 1450-1454.
FORMULA
a(n) <= 2*sqrt(n).
EXAMPLE
a(5) = 4 because the poset with two minimal elements, two maximal elements, and three covering relations between them ["N" shaped] has exactly 5 linear extensions and 4 elements. No smaller poset has 5 linear extensions.
CROSSREFS
Cf. A263860.
Cf. A281723 for the smallest index n = A281723(m) such that a(n) > m.
Sequence in context: A129456 A030412 A329526 * A059686 A101083 A097935
KEYWORD
nonn
AUTHOR
Bridget Tenner, May 11 2009
EXTENSIONS
a(13)-a(102) from François Labelle, Jan 28 2017
STATUS
approved

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Last modified April 24 22:17 EDT 2024. Contains 371964 sequences. (Running on oeis4.)