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A160185
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Triangle read by rows, (1 / ((-1)*A129184 * A007318) + I)) - I, I = Identity matrix.
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1
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1, 2, 1, 5, 3, 1, 15, 9, 4, 1, 52, 31, 14, 5, 1, 203, 121, 54, 20, 6, 1, 877, 523, 233, 85, 27, 7, 1, 4140, 2469, 1101, 400, 125, 35, 8, 1, 21147, 12611, 2625, 2046, 635, 175, 44, 91, 115975, 69161, 30846, 11226, 3488, 952, 236, 54, 10, 1
(list; table; graph; refs; listen; history; internal format)
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OFFSET
| 0,2
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COMMENTS
| Inverse binomial transform of the triangle shifts to left
(= adding I as right border, I = Identity matrix); resulting in reversed rows of A121207.
Left border = Bell numbers, A000110 = eigensequence of Pascal's triangle.
Successive columns from left to right = eigensequences of Pascal's triangle
deleting columns one at a time.
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FORMULA
| Triangle read by rows, 1 / ((-1)*A129184 * A051731 + I), I = Identity matrix. Equals reversal by rows of triangle A121207, then delete right border. A121207 begins: 1; 1, 1; 1, 1, 2 1, 1, 3, 5; ...
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EXAMPLE
| First few rows of the triangle =
1;
2, 1;
5, 3, 1;
15, 9, 4, 1;
52, 31, 14, 5, 1;
203, 121, 54, 20, 6, 1;
877, 523, 233, 85, 27, 7, 1;
4140, 2469, 1101, 400, 125, 35, 8, 1;
21147, 12611, 5625, 2046, 635, 175, 44, 9, 1;
115975, 69161, 30846, 11226, 3488, 952, 236, 54, 10, 1;
...
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CROSSREFS
| Cf. A121207, A000110
Sequence in context: A048471 A067345 A188416 * A188392 A143409 A197387
Adjacent sequences: A160182 A160183 A160184 * A160186 A160187 A160188
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KEYWORD
| nonn,tabl
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AUTHOR
| Gary W. Adamson (qntmpkt(AT)yahoo.com), May 03 2009
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