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A159938 The number of homogeneous trisubstituted linear alkanes. 0
2, 6, 16, 36, 70, 122, 196, 296, 426 (list; graph; refs; listen; history; internal format)
OFFSET

2,1

COMMENTS

See the paper by Valentin Vankov Iliev for details.

REFERENCES

Valentin Vankov Iliev, "A mathematical characterization of the groups of substitution isomerism of the linear alkanes", J. Math. Chem., 45 (2009), xxx-yyy. Page numbers unknown as of today as it is an 'online first' article.

FORMULA

a(n) = (1/3) (2 n^3 - 9 n^2 + 19 n - 12) where n is the number of carbons.

a(n)= 2*A081489(n-1) = (n-1)(2n^2-7n+12)/3. [From R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Apr 28 2009]

EXAMPLE

The number of homogeneous trisubstituted linear alkane with ten carbon atoms is 426.

CROSSREFS

A002522, A033816

Sequence in context: A199477 A060354 A140131 * A145126 A005676 A038503

Adjacent sequences:  A159935 A159936 A159937 * A159939 A159940 A159941

KEYWORD

nonn

AUTHOR

Parthasarathy Nambi (PachaNambi(AT)yahoo.com), Apr 26 2009

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Last modified February 13 11:45 EST 2012. Contains 205467 sequences.