OFFSET
1,8
COMMENTS
Note that for n>1 the last term of the n-th row is the square A000290(n-2).
Row sums are n*(n^2-4*n+5)/2 = 1, 1, 3, 10, 25, 51, 91, 148, 225, ... - R. J. Mathar, Jul 17 2009, Jul 20 2009
Row sums are the positive terms of A162607. - Omar E. Pol, Jul 24 2009
LINKS
G. C. Greubel, Table of n, a(n) for the first 100 rows, flattened
FORMULA
T(n,k) = 1 + k*(n-3), 0<=k<n. - R. J. Mathar, Jul 17 2009
EXAMPLE
Triangle begins:
1;
1, 0;
1, 1, 1;
1, 2, 3, 4;
1, 3, 5, 7, 9;
1, 4, 7, 10, 13, 16;
1, 5, 9, 13, 17, 21, 25;
1, 6, 11, 16, 21, 26, 31, 36;
1, 7, 13, 19, 25, 31, 37, 43, 49;
1, 8, 15, 22, 29, 36, 43, 50, 57, 64;
1, 9, 17, 25, 33, 41, 49, 57, 65, 73, 81;
1, 10, 19, 28, 37, 46, 55, 64, 73, 82, 91, 100;
MATHEMATICA
Table[1 + k*(n-3), {n, 1, 20}, {k, 0, n-1}]// Flatten (* G. C. Greubel, Apr 21 2018 *)
PROG
(PARI) for(n=1, 20, for(k=0, n-1, print1(1 + k*(n-3), ", "))) \\ G. C. Greubel, Apr 21 2018
(Magma) /* As triangle */ [[1 + k*(n-3): k in [0..n-1]]: n in [1..15]]; // G. C. Greubel, Apr 21 2018
CROSSREFS
KEYWORD
AUTHOR
Omar E. Pol, Jul 09 2009
EXTENSIONS
More terms from R. J. Mathar, Jul 17 2009
Typo in row sums corrected by R. J. Mathar, Jul 20 2009
Edited by Omar E. Pol, Jul 24 2009
STATUS
approved