| The a(j) recurrence is a(1)=1; a(2)=31; a(t+2)=32*a(t+1)-a(t)
resulting in terms 1, 31, 991, 31681
The b(j) recurrence is b(1)=1; b(2)=33; b(t+2)=32*b(t+1)-b(t)
resulting in terms 1, 33, 1055, 33727
The n(j) recurrence is n(0)=n(1)=0; n(2)=64; n(t+3)=1023*(n(t+2)-n(t+1))+n(t)
resulting in terms 0, 0, 64, 65472, 66912384 as listed above
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