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The a(j) recurrence is a(1)=1; a(2)=27; a(t+2)=28*a(t+1)-a(t)
resulting in terms 1, 27, 755, 21113
The b(j) recurrence is b(1)=1; b(2)=29; b(t+2)=28*b(t+1)-b(t)
resulting in terms 1, 29, 811, 22679 as listed above
The n(j) recurrence is n(0)=n(1)=0; n(2)=56; n(t+3)=783*(n(t+2)-n(t+1))+n(t)
resulting in terms 0, 0, 56, 43848, 34289136.
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