| The a(j) recurrence is a(1)=1; a(2)=23; a(t+2)=24*a(t+1)-a(t)
resulting in terms 1, 23, 551, 13201
The b(j) recurrence is b(1)=1; b(2)=25; b(t+2)=24*b(t+1)-b(t)
resulting in terms 1, 25, 599, 14351.
The n(j) recurrence is n(0)=n(1)=1; n(2)=48; n(t+3)=575*(n(t+2)-n(t+1))+n(t)
resulting in terms 0, 0, 48, 27600, 15842400 as listed above.
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