|
%I #11 Mar 09 2014 05:55:36
%S 17116004505600,75462255348480000,6219051710415667200,
%T 14031414189615513600,352444116692828160000,835095457414213632000,
%U 59485231752222033838080,64031599488357236736000
%N Numbers with abundancy index sigma(n)/n = 11/2.
%H Michel Marcus, <a href="/A159271/b159271.txt">Table of n, a(n) for n = 1..117</a>
%H G. P. Michon and M. Marcus, <a href="http://www.numericana.com/data/hpn11.htm">Hemiperfect numbers of abundancy 11/2</a> (table with factorizations). [From _Gerard P. Michon_, Jul 01 2009]
%H Walter Nissen, <a href="http://upforthecount.com/math/abundance.html">Abundancy : Some Resources </a>
%o (PARI) is(n)=sigma(n,-1)==11/2 \\ _Charles R Greathouse IV_, Mar 09 2014
%K nonn
%O 1,1
%A _M. F. Hasler_, Apr 21 2009
| 