

A158973


a(n) = count of numbers k <= n such that all proper divisors of k are divisors of n.


4



1, 2, 3, 4, 4, 6, 5, 7, 6, 7, 6, 11, 7, 9, 9, 10, 8, 12, 9, 13, 11, 11, 10, 17, 11, 12, 12, 14, 11, 18, 12, 16, 14, 14, 14, 20, 13, 15, 15, 20, 14, 20, 15, 19, 20, 17, 16, 25, 17, 20, 18, 20, 17, 23, 19, 24, 19, 19, 18, 29, 19, 21, 24, 24, 21, 25, 20, 24, 22, 27, 21, 32, 22, 24, 26
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OFFSET

1,2


COMMENTS

For primes p, a(p) = A036234(p) = A000720(p) + 1.


LINKS

Robert Israel, Table of n, a(n) for n = 1..10000


FORMULA

a(n) = A000005(n) + A004788(n1).  Vladeta Jovovic, Apr 07 2009 (Corrected by Altug Alkan, Nov 25 2015)


EXAMPLE

For n = 8 we have the following proper divisors for k <= n: {1}, {1}, {1}, {1, 2}, {1}, {1, 2, 3}, {1}, {1, 2, 4}. Only k = 6 has a proper divisor that is not a divisor of 8, viz. 3. Hence a(8) = 7.


MAPLE

N:= 1000: # to get a(1) to a(N)
A:= Vector(N, numtheory:tau):
for p in select(isprime, [2, seq(i, i=3..N, 2)]) do
for d from 0 to floor(log[p](N))1 do
R:= [seq(seq(p^d*(i+p*j), j=1..floor((N/p^d  i)/p)), i=1..p1)];
A[R]:= map(`+`, A[R], 1);
od
od:
convert(A, list); # Robert Israel, Nov 24 2015


MATHEMATICA

f[n_] := Block[{d = Most@ Divisors@ n}, Select[Range@ n, Union[Most@ Divisors@ #, d] == d &]]; Array[Length@ f@ # &, {75}] (* Michael De Vlieger, Nov 25 2015 *)


PROG

(MAGMA) [ #[ k: k in [1..n]  forall(t){ d: d in Divisors(k)  d eq k or d in Divisors(n) } ]: n in [1..75] ];
(PARI) a004788(n) = {sfp = Set(); for (k=1, n1, sfp = setunion(sfp, Set(factor(binomial(n, k))[, 1]))); return (length(sfp)); }
a(n) = numdiv(n) + a004788(n1); \\ Altug Alkan, Nov 25 2015


CROSSREFS

Cf. A000040, A000720, A036234.
Sequence in context: A181833 A202650 A228286 * A071323 A071324 A063655
Adjacent sequences: A158970 A158971 A158972 * A158974 A158975 A158976


KEYWORD

nonn


AUTHOR

Jaroslav Krizek, Apr 01 2009


EXTENSIONS

Edited and extended by Klaus Brockhaus, Apr 06 2009


STATUS

approved



