|
|
A158741
|
|
a(n) = 1369*n^2 + 37.
|
|
2
|
|
|
37, 1406, 5513, 12358, 21941, 34262, 49321, 67118, 87653, 110926, 136937, 165686, 197173, 231398, 268361, 308062, 350501, 395678, 443593, 494246, 547637, 603766, 662633, 724238, 788581, 855662, 925481, 998038, 1073333, 1151366, 1232137, 1315646, 1401893, 1490878
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
0,1
|
|
COMMENTS
|
The identity (74*n^2 + 1)^2 - (1369*n^2 + 37)*(2*n)^2 = 1 can be written as A158742(n)^2 - a(n)*A005843(n)^2 = 1.
|
|
LINKS
|
Vincenzo Librandi, X^2-AY^2=1, Math Forum, 2007. [Wayback Machine link]
|
|
FORMULA
|
G.f.: -37*(1 + 35*x + 38*x^2)/(x-1)^3.
a(n) = 3*a(n-1) - 3*a(n-2) + a(n-3).
Sum_{n>=0} 1/a(n) = (coth(Pi/sqrt(37))*Pi/sqrt(37) + 1)/74.
Sum_{n>=0} (-1)^n/a(n) = (cosech(Pi/sqrt(37))*Pi/sqrt(37) + 1)/74. (End)
|
|
MATHEMATICA
|
LinearRecurrence[{3, -3, 1}, {37, 1406, 5513}, 50] (* Vincenzo Librandi, Feb 21 2012 *)
|
|
PROG
|
(Magma) I:=[37, 1406, 5513]; [n le 3 select I[n] else 3*Self(n-1)-3*Self(n-2)+1*Self(n-3): n in [1..40]]; // Vincenzo Librandi, Feb 21 2012
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn,easy
|
|
AUTHOR
|
|
|
EXTENSIONS
|
Comment rewritten, a(0) added and formula replaced by R. J. Mathar, Oct 22 2009
|
|
STATUS
|
approved
|
|
|
|