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A158732 a(n) = 68*n^2 + 1. 2
1, 69, 273, 613, 1089, 1701, 2449, 3333, 4353, 5509, 6801, 8229, 9793, 11493, 13329, 15301, 17409, 19653, 22033, 24549, 27201, 29989, 32913, 35973, 39169, 42501, 45969, 49573, 53313, 57189, 61201, 65349, 69633, 74053, 78609, 83301, 88129, 93093, 98193, 103429 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,2
COMMENTS
The identity (68*n^2 + 1)^2 - (1156*n^2 + 34)*(2*n)^2 = 1 can be written as a(n)^2 - A158731(n)*A005843(n)^2 = 1.
LINKS
Vincenzo Librandi, X^2-AY^2=1, Math Forum, 2007. [Wayback Machine link]
FORMULA
a(n) = 3*a(n-1) - 3*a(n-2) + a(n-3).
G.f.: -(1 + 66*x + 69*x^2)/(x-1)^3.
From Amiram Eldar, Mar 22 2023: (Start)
Sum_{n>=0} 1/a(n) = (coth(Pi/(2*sqrt(17)))*Pi/(2*sqrt(17)) + 1)/2.
Sum_{n>=0} (-1)^n/a(n) = (cosech(Pi/(2*sqrt(17)))*Pi/(2*sqrt(17)) + 1)/2. (End)
MATHEMATICA
LinearRecurrence[{3, -3, 1}, {1, 69, 273}, 50] (* Vincenzo Librandi, Feb 18 2012 *)
68*Range[0, 40]^2+1 (* Harvey P. Dale, Sep 16 2019 *)
PROG
MAGMA) I:=[1, 69, 273]; [n le 3 select I[n] else 3*Self(n-1)-3*Self(n-2)+1*Self(n-3): n in [1..40]]; // Vincenzo Librandi, Feb 18 2012
(PARI) for(n=0, 40, print1(68*n^2 + 1", ")); \\ Vincenzo Librandi, Feb 18 2012
CROSSREFS
Sequence in context: A183447 A296126 A188546 * A069216 A158736 A262456
KEYWORD
nonn,easy
AUTHOR
Vincenzo Librandi, Mar 25 2009
EXTENSIONS
Comment rewritten, a(0) added and formula replaced by R. J. Mathar, Oct 22 2009
STATUS
approved

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Last modified April 24 09:18 EDT 2024. Contains 371935 sequences. (Running on oeis4.)