OFFSET
1,1
COMMENTS
The identity (900*n - 1)^2 - (900*n^2 - 2*n)*30^2 = 1 can be written as A158409(n)^2 - a(n)*30^2 = 1.
LINKS
Vincenzo Librandi, Table of n, a(n) for n = 1..10000
E. J. Barbeau, Polynomial Excursions, Chapter 10: Diophantine equations (2010), pages 84-85 (row 15 in the first table at p. 85, case d(t) = t*(30^2*t-2)).
Index entries for linear recurrences with constant coefficients, signature (3,-3,1).
FORMULA
G.f.: 2*x*(449 + 451*x)/(1-x)^3. - Bruno Berselli, Dec 08 2011
a(n) = 3*a(n-1) - 3*a(n-2) + a(n-3). - Vincenzo Librandi, Feb 12 2012
MATHEMATICA
LinearRecurrence[{3, -3, 1}, {898, 3596, 8094}, 50] (* Vincenzo Librandi, Feb 12 2012 *)
PROG
(Magma) I:=[898, 3596, 8094]; [n le 3 select I[n] else 3*Self(n-1)-3*Self(n-2)+1*Self(n-3): n in [1..50]]; // Vincenzo Librandi, Feb 12 2012
(PARI) for(n=1, 40, print1(900*n^2 - 2*n", ")); \\ Vincenzo Librandi, Feb 12 2012
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Vincenzo Librandi, Mar 18 2009
STATUS
approved