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The primitive terms in A158235 are the ones for which the repdigit is squarefree. Hence n^2 = d*(b^k-1)/(b-1) with d squarefree and d<b<n.
Table of n, a(n) for n=1..39.
105339^2 = 333 in base 60817.
Sequence in context: A153368 A068600 A158235 * A076851 A164576 A058497
Adjacent sequences: A158242 A158243 A158244 * A158246 A158247 A158248
T. D. Noe, Mar 14 2009