|
| |
| |
|
|
|
511, 1023, 1535, 2047, 2559, 3071, 3583, 4095, 4607, 5119, 5631, 6143, 6655, 7167, 7679, 8191, 8703, 9215, 9727, 10239, 10751, 11263, 11775, 12287, 12799, 13311, 13823, 14335, 14847, 15359, 15871, 16383, 16895, 17407, 17919, 18431, 18943
(list; graph; refs; listen; history; internal format)
|
|
|
|
OFFSET
| 1,1
|
|
|
COMMENTS
| The identity (512*n-1)^2-(256*n^2-n)*32^2 = 1 can be written as a(n)^2-A158010(n)*32^2 = 1. - Vincenzo Librandi, Feb 10 2012
|
|
|
LINKS
| Vincenzo Librandi, Table of n, a(n) for n = 0..10000
E. J. Barbeau, Polynomial Excursions, Chapter 10: Diophantine equations (2010), pages 84-85 (row 14 in the first table at p. 85, case d(t) = t*(16^2*t-1)).
|
|
|
FORMULA
| G.f.: x*(x+511)/(x-1)^2. - Vincenzo Librandi, Feb 10 2012
a(n) = 2*a(n-1)-a(n-2). - Vincenzo Librandi, Feb 10 2012
|
|
|
MATHEMATICA
| LinearRecurrence[{2, -1}, {511, 1023}, 50] (* Vincenzo Librandi, Feb 10 2012 *)
|
|
|
PROG
| (MAGMA) I:=[511, 1023]; [n le 2 select I[n] else 2*Self(n-1)-Self(n-2): n in [1..50]]; // Vincenzo Librandi, Feb 10 2012
(PARI) for(n=1, 50, print1(512*n - 1", ")); \\ Vincenzo Librandi, Feb 10 2012
|
|
|
CROSSREFS
| Cf. A158010.
Sequence in context: A023691 A045118 A043451 * A032656 A031899 A143036
Adjacent sequences: A158008 A158009 A158010 * A158012 A158013 A158014
|
|
|
KEYWORD
| nonn,easy,changed
|
|
|
AUTHOR
| Vincenzo Librandi (vincenzo.librandi(AT)tin.it), Mar 11 2009
|
| |
|
|